ACTIVITY 1: The Four Tables | ANSWER AND EXPLANATION

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Table 1: Moon / Tea
Table 2: Key / Bookmark
Table 3: Star / Seeds
Table 4: Leaf / Chocolate

Seeds is with Star, so Leaf cannot have Seeds. Clue 4 also rules out Tea and Bookmark for Leaf. Leaf must have Chocolate.

Chocolate is at table 4, so Leaf is at table 4. Moon is at an end and cannot share table 4 with Leaf. Moon is at table 1.

Tea must sit directly before Bookmark. Chocolate already occupies table 4. The pair can therefore occupy tables 1 and 2, or tables 2 and 3.

Suppose Tea were at table 2 and Bookmark at table 3. Seeds would be left at table 1. But Seeds must go with Star, and table 1 already has Moon. That pair cannot work.

Tea is therefore at table 1, Bookmark at table 2, and Seeds at table 3. Star goes with Seeds at table 3. The last sign, Key, goes at table 2.


ACTIVITY 2: The Welcome Route | ANSWER AND EXPLANATION

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Gate -> Bell -> Clock -> Porch -> Fountain -> Lantern -> Table

The required Clock-to-Porch move and the no-revisit rule mean the route must enter Porch from Clock.

Start by testing Gate to Bench. If Clock comes next, the route through Porch cannot include Bell and finish in six moves. If Fountain comes next, the only continuing route through the required places needs seven moves. So the first move must reach Bell.

After Bell, choosing Lantern also forces a seven-move route through Fountain, Bench, Clock and Porch before Table. Therefore go from Bell to Clock, then directly to Porch.

From Porch, Table would finish too soon and omit Fountain. Continue to Fountain. Bench would leave only already-visited exits, so choose Lantern, then Table.

Check each printed connection in the completed route. It uses six moves and seven different places, includes Bell and Fountain, and travels directly from Clock to Porch.


ACTIVITY 3: The Message Mender | ANSWER AND EXPLANATION

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PASS IT ON

Strip 1: 3 + 2 = 5, and 2 + 5 = 7. Replace its third number, 6, with 5. Row 3, column 2 gives P.

Strip 2: the second, third and fourth numbers already satisfy 1 + 2 = 3. To also make first + 1 = 2, replace the first number with 1. Row 1, column 1 gives A.

Strip 3: 2 + 1 = 3 already works. Replace the fourth number with 1 + 3 = 4. Row 2, column 1 gives S.

Strip 4: keeping first 2, third 3 and fourth 4 requires second 1: both 2 + 1 = 3 and 1 + 3 = 4. Replace the second number, 4, with 1. Row 2, column 1 gives S.

Strip 5: 1 + 3 = 4 already works. Replace the fourth number with 3 + 4 = 7. Row 1, column 3 gives I.

Strip 6: keeping first 2, third 5 and fourth 8 requires second 3: both 2 + 3 = 5 and 3 + 5 = 8. Replace the second number, 1, with 3. Row 2, column 3 gives T.

Strip 7: 1 + 4 = 5 already works. To also make first + 1 = 4, replace the first number with 3. Row 3, column 1 gives O.

Strip 8: keeping first 4 and second 1 gives third 5 and fourth 6. Replace the third number, 7, with 5. Row 4, column 1 gives N.

Read the eight letters in the printed strip order and insert only the specified two spaces.

Each first/second pair determines the other two numbers. Of the 16 allowed pairs, only one differs from each printed strip in exactly one position. This fixes the letter without a word guess.
